# sort() will change the original list into a sorted list<br /> vowels = [‘e’, ‘a’, ‘u’, ‘o’, ‘i’]<br /> vowels.sort()<br /> # Output:<br /> # [‘a’, ‘e’, ‘i’, ‘o’, ‘u’]</p> <p># sorted() will sort the list and return it while keeping the original<br /> sortedVowels = sorted(vowels)<br /> # Output:<br /> # [‘a’, ‘e’, ‘i’, ‘o’, ‘u’]

a_list = [3,2,1]<br /> a_list.sort()

vowels = [‘e’, ‘a’, ‘u’, ‘o’, ‘i’]<br /> vowels.sort()

l=[1,3,2,5]<br /> l= sorted(l)<br /> print(l)<br /> #output=[1, 2, 3, 5]<br /> #or reverse the order:<br /> l=[1,3,2,5]<br /> l= sorted(l,reverse=True)<br /> print(l)<br /> #output=[5, 3, 2, 1]

thislist = [“orange”, “mango”, “kiwi”, “pineapple”, “banana”]<br /> thislist.sort()<br /> print(thislist)

# example list, product name and prices<br /> price_data = [[‘product 1’, 320.0],<br /> [‘product 2’, 4387.0],<br /> [‘product 3’, 2491.0]]</p> <p># sort by price<br /> print(sorted(price_data, key=lambda price: price[1]))

l = [64, 25, 12, 22, 11, 1,2,44,3,122, 23, 34]</p> <p>for i in range(len(l)):<br /> for j in range(i + 1, len(l)):</p> <p> if l[i] > l[j]:<br /> l[i], l[j] = l[j], l[i]</p> <p>print l

>>> a = [5, 2, 3, 1, 4]<br /> >>> a.sort()<br /> >>> a<br /> [1, 2, 3, 4, 5]<br />

old_list = [3,2,1]<br /> old_list.sort()

“””Sort in ascending and descending order”””<br /> list_test = [2, 1, 5, 3, 4]</p> <p>#ascending is by default for sort<br /> #Time Complexity: O(nlogn)<br /> list_test.sort()</p> <p>#For descending order<br /> #Time Complexity: O(nlogn)<br /> list_test.sort(reverse=True)</p> <p>#For user-define order<br /> list_test.sort(key=…, reverse=…)